Mar 092009
Jenna Jameson and Danni Ashe walk 6 miles in opposite directions, starting from the same point on a road.
Jenna walks 6 miles North and Danni 6 miles South. At the 6 mile mark, Jenna turns left and walks for 8 miles and so does Danni. Right at the 8 mile mark both Danni and Jenna stop. exactly How many miles is Jenna from Danni?
20 miles miles
let they started from pt.O
and both walked 6 miles in opposite directions i.e, A and B
now they turned left and reached C and D
now distance of C and D is
(using Pythagoras')
((6^2)+(8^2))^1/2 + ((6^2)+(8^2))^1/2
(36+64)^1/2 +(36+64)^1/2
100^1/2+100^1/2
10+10
20
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20 miles miles
let they started from pt.O
and both walked 6 miles in opposite directions i.e, A and B
now they turned left and reached C and D
now distance of C and D is
(using Pythagoras')
((6^2)+(8^2))^1/2 + ((6^2)+(8^2))^1/2
(36+64)^1/2 +(36+64)^1/2
100^1/2+100^1/2
10+10
20
References :
me
Jenna goes west and Danni goes east, so the distance between them is the hypotenuse of a triangle with horizontal side 16, vertical side 12, so the distance is 20 miles (using Pythagoras')
References :
When they both walk North and South, they each walk 6 miles in opposite directions, so their vertical distance apart is 12 miles.
When they turn left, one walks 8 miles East and the other 8 miles West, so their horizontal distance apart is 16 miles.
You can now apply the Pythagorean theorem. 12-16 are multiples of 3 and 4, so you have a 3-4-5 right triangle scaled by a factor of 4. Therefore, the triangle is 12-16-20, and the distance is 20 miles.
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20 miles answers as given above
BUT only if assuming they walk normally, not walking side-way or walking backwards. also assume the earth is flat.
sorry if i make the answer "un-fun"
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I think that they are 20 miles apart.
If you were to draw this on a piece of paper, it would form two right triangles, each having leg measures of 6 and 8. The distance that they are apart is the sum of the two hypotenuses. To find the hypotenuse (c), where a nd b are legs of the right triangle:
c² = a² + b²
c² = (6)² + (8)²
c² = 36 + 64
c² = 100
c = √100
c = 10 miles
Since both of the triangles are congruent, 10 + 10 = 20. And THAT is how I came up with 20 miles.
References :
Fred beat me to it, it is only 20 miles if you consider plane geometry. Because we assume they are walking on a curved surface (ie, Earth's surface) the actual geometric distance – given by a straight line that separates them – would have to go through the sphere and would be and would be slightly less than 20 miles.
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20
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