Feb 192009

There are ten golden numbers: 64, 91, 104, 187, 231, 268, 286, 300, 393, and 425. You need to choose 5 numbers that aren’t any of the golden numbers. With these numbers, you need to get them to equal each of these numbers. You may only use addition and subtraction, but you can use the numbers as many times as you want, in any number of ways.
The score is determined by how many times you used one of your chosen numbers to make the calculation.

I’m trying to get less than 30 total. Can someone help please?

You said “in any number of ways”

does that include spinning the “6″ upside down as in 16 = 61?

Inserting a number…(adding it to the middle) as in 1 + 200 = 210

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One Comments to “Can Someone Give Me a Solution to This Math Puzzle?”

  1. frodo says:

    You said “in any number of ways”

    does that include spinning the “6″ upside down as in 16 = 61?

    Inserting a number…(adding it to the middle) as in 1 + 200 = 210

    References :

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